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Archimedess Principle1. Weight = mass x 9.80 g/cm3W= 45g x 9.80 NW= 44,100 dynes2. fortunate force (calculated) = weight in air weight in waterBF = 44,100 dynes 38710 dynesBF = 5390 dynes3. hoi polloi of Water = radius2 x lengthV= (.63cm) (4.65cm)V= 5.80 cm 4. Buoyant force ( measur adapted) = mass in air/ densityBF= (44,100 g) / (7.76 g/cm3)BF= 5684 cm35. % difference = BF calculated BF measured/ BF measured% difference = 5390 5684 / 5684% difference = 5.4 %6. Density = Mass / VolumeDensity = 45 g / 5.80 cm3Density = 7.76 g/cm37. Volume of woodland = length x width x heightV = (7.62cm) (7.63cm) (3.86 cm)V = 224. 42 cm3Questions2.) Because an overweight person displaces more mobile when stepping into a pool. By displacing more fluid, the person creates a greater buoyant force making it easier for him to swim.5.c) By placing a battery into the water with a locomote rod into its deep cylindrical cavity it is quite easy to determine the condition of the battery. The diluted ba ttery will have a much higher(prenominal) density than that of a highly charged battery. From the observation of how the battery floats you can tell its condition.8.) We were able to recover the volume of displace water in use II quite easily. First we placed a large tupperware container on the table and in it a smaller container filled to the top with water. When the block of wood was placed in the container, water fell out of the smaller container into the larger container. By placing the water which fell out of the smaller container into a cylinder, you are able to measure the volume of displaced water.9.) No I did not use Archimedess principal to find the densities. I used the density formula of dividing the mass by the volume. We find the densities and compare them to the densities of water to help understand the mechanics of buoyant force.DiscussionIn part two of the lab dealing with Archimedess principle, we were canvas the buoyant force of a block of wood to its weight in dynes. The first step of the operation dealt with measuring the quantity of displaced water. We did this using two containers, unmatched small and one large, and filled the small container to the brim with water. By placing the block of wood in the small container and using a graduated cylinder, we were able to find the amount of water displaced by the block.